Using the concept of a half-life, and without doing any written calculations, determine what the activity 9 minutes later is. At a given instant, the activity of a certain sample of thallium is 2400 Bq. The thallium Subscript 81 Superscript 208 Baseline Tl nucleus is radioactive, with a half-life of 3.053 min. Type in your answer with 3 significant figures. Calculate the atomic mass (in amu) of the element. Take air gas constant (R) = 0.287 kJ/(kg.oK) An imaginary element (X) on Mars is composed of three isotopes, 10.68% of isotope X-95 with a mass of 95.0 amu, 16.90% of isotope X-96 with a mass of 96.0 amu, and 72.42% of isotope X-97 with a mass of 97.0 amu. Determine the volume of the second tank and the final equilibrium pressure of air. The valve is opened and the whole system is brought to thermal equilibrium with the surrounding of 20 oC. What offspring would you expect from (a) the cross of a barred hen to a non-barred rooster? (b) the cross of an Fl rooster from part (a) to one of his sisters? A 1-m3 tank containing air 25 oC & 500 kPa is connected to another tank containing 5 kg of air at 35 oC & 200 kPa through a valve. Now that we know the value of t₁, we can find the value of D. We can see that both of these left sides are equal to the same thing, then we must have: T₂ = t₁ + 2.5s and replace it on the second equation: Where t₁ is the time that the light needs to reach the student, t₂ is the time the sound needs to reach the student, and D is the distance between the student and the ligthing. So there is a little time between when the lighting happens and the student sees it, that will also have an impact on the distance to the lighting. Light travels and impacts the student's eyes, at this moment he sees the flash of light, this is what we consider the t = 0.The student sees the "flash" when the light impacts on his eyes. Now, notice that there is an intrinsic problem with this question. We want to find the distance between the student and the lighting given that we know the time that passes between the moment he sees the lighting and the moment he hears it. The mass flow is that much amount per minute The gas constant for air is R = 53.35 (ft*lb)/(lbm* °R) With the gas state equation we calculate the mass: The G terms are mass flows, however we have volume flow of air. Tfin = (-Gw * Cpw * Δt) / (Ga * Cpa) + ti Tfin - ti = (-Gw * Cpw * Δt) / (Ga * Cpa) We split the heat into the heat transferred by the air and the heat trnasferred by the water: Also does not perform or consume any work L = 0. The heat exchanger is running at a steady state, so ΔU = 0. Ounce Per Square Inch -> foot of water 4☌ or 39.Air has a specific heat at constant pressure of:.Ounce Per Square Inch -> dyne per square centimeter.Ounce Per Square Inch -> kilogram force per square millimeter.Ounce Per Square Inch -> inch of water 4☌ or 39.2☏.Ounce Per Square Inch -> meganewton per square inch.Ounce Per Square Inch to random (pressure units) Random PRESSURE units foot of water 4☌ or 39.2☏ millipascals kilogram force per square millimeter terapascals foot of water 15.5☌ or 60☏ ounce per square yard ksi micropascals decapascals barye (Ounce Per Square Inch) to (Kilopascals) conversions In relation to the base unit of => (pascals), 1 Ounce Per Square Inch (oz/in2) is equal to 430.92233 pascals, while 1 Kilopascals (kPa) = 1000 pascals. How to convert Ounce Per Square Inch to Kilopascals (oz/in2 to kPa)?ġ x 0.43092233 kPa = 0.43092233 Kilopascals.Īlways check the results rounding errors may occur. The base unit for pressure is pascals (Non-SI Unit) Conversion: Ounce Per Square Inch to Kilopascals
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